Equivalent weight of K2Cr2O7 in acidic medium is 49 g/mol. Hope this helps you.

How do you find the equivalent weight of K2Cr2O7 in acidic medium?

Potassium dichromate in an acidic medium is a strong oxidizer. It means it gains electrons during the redox reaction. The total number of electrons involved in this change is 6. Equivalent weight = molecular weight / no of e- = 294 / 6 = 49 g/mol.

What will be the equivalent weight of K2Cr2O7 in basic medium?

We will get the final value of equivalent weight = 49 g/mol.

How do you find the equivalent weight of an acid medium?

Answer: (4) Equivalent weight can be calculated by using the formula. Equivalent weight = Molar mass/number of electrons lost or gained (n) In acidic medium: MnO4- + 8H +5e– –> Mn2 + 4H2O. Here n = 5. In basic medium: MnO4−+ e− → MnO42− Here n = 1. In neutral medium: Mno4– + 4H+ + 3e− –> MnO2+ 2H2O. Here n = 3.

What is the equivalent weight of K2Cr2O7 during titration with sodium thiosulphate in the acidic medium?

⋅ ⋅ . M.m. K2Cr2O7 = 294,187 g. 1. Load a burette with standardised sodium thiosulphate solution.

What is the formula for equivalent weight?

Equivalent Weight = Molecular weight/ Valency

Also, read: Chemical Reaction.

What is the equivalent weight of FAS?

-Hence, the equivalent weight of ferrous ammonium sulphate is 392.13g/mol.

Why K2Cr2O7 is orange in acidic and yellow in basic medium?

Answer: This is because in basic medium, potassium dichromate forms chromate ions which is yellow in colour while in acidic medium forms dichromate ions. Dichro. ate ions are red in colour while chromateions are yellow in colour.

What is the N factor of K2Cr2O7 in neutral medium?

Hence the n-factor is 6.

How do you find the N factor of K2Cr2O7 in the basic medium?

The equation for potassium dichromate in basic medium follows:
Net ionic equation follows:Oxidation state of Chromium in reactant side:Oxidation state of Chromium at product side:Therefore, the n-factor for this atom will be (6 – 3) = 3.

When ferrous sulphate acts as reductant its equivalent weight is?

So, the molecular weight of ferrous sulphate is 151.8. -Equivalent weight of ferrous sulphate = molecular weight of ferrous sulphate/ involved electron. So, equivalent weight of ferrous sulphate which is present as reductant is 151.8 which is equal to the molecular weight of ferrous sulphate.

What is the equivalent of mno4 in acidic medium?

So, our answer is 31.6 per equivalent.

What is equivalent weight of KMnO4 in acidic medium?

The equivalent weight of KMnO4 in acidic medium is 31.6 .

What is the equivalent weight of Hypo?

The weight equivalent is the gram molecular weight divided by the number of electrons lost or obtained by each molecule; this is (248.17/1) g for sodium thiosulfate (Na2S2O3. 5H2O).

What is equivalent weight of sodium thiosulphate?

The equivalent weight of sodium thiosulphate = molecular weight of sodium thiosulphate. Therefore, the equivalent weight of sodium thiosulphate is 248.

What is the equivalent weight of oxalic acid?

Equivalent mass of oxalic acid = molecular mass of oxalic acid/2 = 126g/2 = 63 grams. Therefore, the equivalent weight of oxalic acid is 63 grams.

What is meant by equivalent weight of an acid?

The equivalent weight of an acid is the mass of acid required to generate one mole of hydrogen (hydronium) ion in aqueous solution. For an acid that contains more than one ionizable hydrogen, the equivalent weight is a fraction of the molar mass.

How do you calculate equivalents?

Calculating Molar Equivalents

To calculate molar equivalents for each reagent, divide the moles of that reagent by the moles of the limiting reagent: Note that the molar equivalency of sodium benzoate is 1. This is because sodium benzoate is the limiting reagent.