In the chlorate ion (ClO3-), the oxidation number of Cl +5, and the oxidation number of O is -2. In a neutral atom or molecule, the sum of the oxidation numbers must be 0. In a polyatomic ion, the sum of the oxidation numbers of all the atoms in the ion must equal the charge on the ion.

How do you find the oxidation number of Cl in ClO3?

So, if we assume the oxidation state of chlorine as $x$, then: $x + 3 times ( – 2) = – 1$. So, the oxidation state of ${text{Cl}}$ in ${text{ClO}}_{text{3}}^{text{ – }}$ is $ + 5$. $therefore $ The correct option is option B, i.e. $ + 5$.

What is the charge of Cl in ClO3?

There are one chlorine atom and three oxygen atoms in the chlorate ion. Also there is a -1 charge on the ClO3- ion. Chlorine and oxygen are located at 7 and 6 groups respectively in the periodic table. So chlorine has seven electrons in its valence shell.

What is the oxidation number of chlorine in Al ClO3 3?

The oxidation number of Cl in Al(ClO3)3 is +5.

What is the oxidation number of chlorine in ClO3 a +5 B +3 C +4 D +2?

Answer: Oxidation state of chlorine is +5 and oxidation state of oxygen is -2.

What is the oxidation number of the chlorine atom in the chlorate ion ClO3 and in molecular chlorine Cl2?

Chlorine can also bond with oxygen to give the chlorate ion, ClO3-, in which the chlorine atom has an oxidation state of +5. This ion is named as chlorate(V) using IUPAC nomenclature. The oxidation number of chlorine increases from 0 in Cl2 to +1 in NaClO and it is oxidised.

How many double bonds are in ClO3?

Since ClO3 is a polyatomic atom (chlorate ion) with a charge of -1 it is represented with 1 chlorine atom and 3 oxygen atoms. The chlorine atom has two double bonds with two oxygen atoms and a single bond with the last oxygen atom.

What is the bond order of ClO3?

For ClO3-, the bond order is 5/3.

What is the change in oxidation number of fluorine in the following reaction?

Here, we have observed that the oxidation number of F increases from 0 in F2 to +1 in HOF. Also, the oxidation number decreases from 0 in F2 to -1 in HF. Thus, in the above reaction, F is both oxidized and reduced. Hence, the given reaction is a redox reaction.

What is the oxidation number of S in s2o3 2?

Stefan V. Oxygen would have an oxidation state of −2 , therefore sulfur would have an oxidation state of +2 .

What is the oxidation state of chromium in cr2o72?

The sum of the oxidation numbers in Cr2O72-, a polyatomic ion, is -2, the charge of the ion. There are seven oxygen atoms, so the total charge is − 2⋅7 = − 14. So, a chromium atom here has an oxidation number of + 6.

What is the oxidation number of sulfur in H2SO4?

Explanation: In H2SO4 , hydrogen exists in its usual +1 state, and oxygen exists in its −2 state. So, sulfur exists in the +6 state.

What is the oxidation number of Hg in hgl2?

The oxidation number of mercury in mercury diiodide is 2.